We have studied the operation and construction of Pressure to Current converter , now lets discuss about Current to Pressure converter. As the name suggests, in this instance, current signal is converted into pneumatic i.e Pressure signal.
In some control systems, we will not need a current signal as output and we need a pneumatic signal, for example, if you want to connect the output of one system as input of hydraulic system, we cannot directly give a current signal as an input to hydraulic signal; here, we must give a pneumatic signal. In those cases we need current to pressure converter. Lets see the operation of Current to Pressure converter.
pressure, same as we did in P to I converter. Electromagnet is used to take the current signal as input. Springs are used to keep the nozzle stable.
Flapper Nozzle arrangement :- As we have already discussed during Pressure to Current converter, to control the pressure it is used. The output pressure will change according to the movement of flapper.
Electro Magnet: It is the element which acts as a magnet if current is passed through it, there will be a coil which is wound around a electromagnetic material. If current passes through the coil, it acts as a magnet.
In the Current to Pressure converter, we usually give input current signal as 4 - 20 mA . We also give a continuous supply of 20 P.S.I to the Flapper Nozzle apparatus. As we give current signal, Electromagnet gets activated. If the current is more, then the power of magnet will get increased. The Flapper of the Flapper-Nozzle instrument is connected to Pivot so that it can move up and down and a magnetic material was attached to other end of flapper and it is kept near the electromagnet.
As the magnet gets activated. the flapper moves towards the electromagnet and the nozzle gets closed to some extent. So the some part of 20 P.S.I supplied will escape through nozzle and remaining pressure will come as output. If the current signal is high, then power of the magnet will increase, then flapper will move closer to the nozzle, so less pressure will escape through nozzle and output pressure increases.
In this way the output pressure will be proportional to the input current.
For the input current of 4 - 20 mA we can get the output pressure of 3 - 15 P.S.I
I hope you understood above operation, if you still have any doubts, ask them as a comment to this article. I am happy to clear those doubts.
In some control systems, we will not need a current signal as output and we need a pneumatic signal, for example, if you want to connect the output of one system as input of hydraulic system, we cannot directly give a current signal as an input to hydraulic signal; here, we must give a pneumatic signal. In those cases we need current to pressure converter. Lets see the operation of Current to Pressure converter.
I to P converter
We can construct a I to P converter by using Flapper-Nozzle arrangement, two springs and a Electro magnet. Flapper Nozzle arrangement is used to controlpressure, same as we did in P to I converter. Electromagnet is used to take the current signal as input. Springs are used to keep the nozzle stable.
Flapper Nozzle arrangement :- As we have already discussed during Pressure to Current converter, to control the pressure it is used. The output pressure will change according to the movement of flapper.
Electro Magnet: It is the element which acts as a magnet if current is passed through it, there will be a coil which is wound around a electromagnetic material. If current passes through the coil, it acts as a magnet.
Operation of I to P converter
In the Current to Pressure converter, we usually give input current signal as 4 - 20 mA . We also give a continuous supply of 20 P.S.I to the Flapper Nozzle apparatus. As we give current signal, Electromagnet gets activated. If the current is more, then the power of magnet will get increased. The Flapper of the Flapper-Nozzle instrument is connected to Pivot so that it can move up and down and a magnetic material was attached to other end of flapper and it is kept near the electromagnet.
As the magnet gets activated. the flapper moves towards the electromagnet and the nozzle gets closed to some extent. So the some part of 20 P.S.I supplied will escape through nozzle and remaining pressure will come as output. If the current signal is high, then power of the magnet will increase, then flapper will move closer to the nozzle, so less pressure will escape through nozzle and output pressure increases.
In this way the output pressure will be proportional to the input current.
For the input current of 4 - 20 mA we can get the output pressure of 3 - 15 P.S.I
I hope you understood above operation, if you still have any doubts, ask them as a comment to this article. I am happy to clear those doubts.
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